Matematika aYo kaaa tolong menolong ​

marianemclaughlinulv – April 06, 2023

aYo kaaa tolong menolong ​

pembahasan :

( ba⁻²/(ba) )⁻¹ . (3a⁻¹/b )⁻³ =

( a⁻²⁻¹)⁻¹ . 3⁻³a⁻¹ˣ⁻³/ b⁻³ =

a⁻³ˣ ⁻¹ .3⁻³a³b³ =

a³ . 1/27 . a³b³ =

1/27 .a⁶b³

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