aYo kaaa tolong menolong
pembahasan :
( ba⁻²/(ba) )⁻¹ . (3a⁻¹/b )⁻³ =
( a⁻²⁻¹)⁻¹ . 3⁻³a⁻¹ˣ⁻³/ b⁻³ =
a⁻³ˣ ⁻¹ .3⁻³a³b³ =
a³ . 1/27 . a³b³ =
1/27 .a⁶b³
[answer.2.content]bobcat 763 manual download
pembahasan :
( ba⁻²/(ba) )⁻¹ . (3a⁻¹/b )⁻³ =
( a⁻²⁻¹)⁻¹ . 3⁻³a⁻¹ˣ⁻³/ b⁻³ =
a⁻³ˣ ⁻¹ .3⁻³a³b³ =
a³ . 1/27 . a³b³ =
1/27 .a⁶b³
[answer.2.content]